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Question
Using suitable identities, evaluate the following.
98 × 103
Evaluate
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Solution
We have,
98 × 103 = (100 – 2)(100 + 3)
= (100)2 + (–2 + 3)100 + (–2) × 3 ...[Using the identity, (x + a)(x + b) = x2 + (a + b)x + ab]
= 10000 + 100 – 6
= 10094
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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 233]
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