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Question
Using slopes, prove that the points (−1, −2), (5, 1) and (11, 4) are collinear.
Sum
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Solution
Given:
- A = (x1, y1) = (−1, −2)
- B = (x2, y2) = (5, 1)
- C = (x3, y3) = (11, 4)
The formula for slope (m) is:
`m = (y_2 - y_1)/(x_2 - x_1)`
⇒ Calculate the Slope of AB(m1):
`m_1 = (1 - (-2))/(5 - (-1))`
`m_1 = (1 + 2)/(5 + 1)`
`m_1 = 3/6`
∴ `m_1 = 1/2`
⇒ Calculate the Slope of BC(m2):
`m_2 = (4 - 1)/(11 - 5)`
`m_2 = 3/6`
∴ `m_2 = 1/2`
Since the Slope of AB = Slope of BC `(1/2 = 1/2)`, the line segments AB and BC are parallel. Because they share a common point B, the points A, B, and C lie on the same straight line.
Hence, the points (−1, −2), (5, 1) and (11, 4) are collinear.
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