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Questions
Using Kirchhoff’s laws, obtain the equation of the balanced state in Wheatstone Bridge.
Derive the condition for which a Wheatstone Bridge is balanced.
Derivation
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Solution
The Wheatstone Bridge is as shown in the figure

Applying Kirchhoff’s II law to mesh ABDA
I1P + IgG – I2R = 0 ...(1)
For the mesh BCDB:
(I1 − Ig)Q + [−(I2 + Ig)S] + [−IgG] = 0 ...(2)
When the bridge is balanced, no current flows through the galvanometer.
i.e., Ig = 0 ...(3)
∴ From equations (1), (2), and (3)
I1P = I2R ...(4)
I1Q = I2S ...(5)
From equations (4) and (5),
`P/Q = R/S`
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