Question

 Using determinants, find the values of k, if the area of triangle with vertices (–2, 0), (0, 4) and (0, k) is 4 square units. 

Answer 1

 A(ΔABC ) = 4

1(0-0)-1(-2K)+1(-8-0)=±8
2K - 8 = ±8
2K = ±8 + 8

∴ K =`16/2` or K=`0/2 rArr` K =8 or K = 0