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Urea is a very important nitrogenous fertilizer. Its formula is CON2H4. Calculate the percentage of carbon in urea. (C = 12, O = 16, N = 14 and H = 1) - Chemistry

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Question

Urea is a very important nitrogenous fertilizer. Its formula is CON2H4. Calculate the percentage of carbon in urea. (C = 12, O = 16, N = 14 and H = 1)

Numerical
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Solution

The formula of urea is NH2CONH2 i.e CON2H4
Molar mass = 60 g/mol

Atomic mass of C = 12 & number of atoms = 1

∴ Percentage of carbon in urea = `12/60 xx 100` = 20%

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Percentage Composition, Empirical and Molecular Formula
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Chapter 1: The Language of Chemistry - Exercise 1 (C) [Page 19]

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Selina Concise Chemistry [English] Class 9 ICSE
Chapter 1 The Language of Chemistry
Exercise 1 (C) | Q 17 | Page 19

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