Advertisements
Advertisements
Question
Two urns contain the set of balls as given in the following table
| Title | White | Red | Black |
| Urn 1 | 10 | 6 | 9 |
| Urn 2 | 3 | 7 | 15 |
One ball is drawn from each urn and find the probability that
- both balls are red
- both balls are of the same colour.
Advertisements
Solution
i. Let A be the event of drawing a red from urn 1
P(A) = `6/25`
Let B be the event of selecting a red ball in urn 2
P(B) = `7/25`
∴ P(both balls are red) = P(A) × P(B) ........[∵ the events are independent]
= `6/25 xx 7/25`
= `42/625`
ii. Let W1, R1, B1 represent white, red, and black balls drawn from urn 1 and W2, R2, B2 represent white, red, and black balls from urn 2.
P(both balls are of the same colour) = P(W1W2) + P(R1R2) + P(B1B2) ...........[∵ Events are mutually exclusive]
= P(W1) P(W2) + P(R1) P(R2) + P(B1) P(B2) .......[∵ Events are independent]
= `10/25 xx 3/25 + 6/25 xx 7/25 + 9/25 xx 15/25`
= `1/625 [30 + 42 + 135]`
= `207/625`
