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Two tuning forks having frequencies 320 Hz and 340 Hz are sounded together to produce sound waves. The velocity of sound in air is 340 m/s. Find the difference in wavelength of these waves.

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Question

Two tuning forks having frequencies 320 Hz and 340 Hz are sounded together to produce sound waves. The velocity of sound in air is 340 m/s. Find the difference in wavelength of these waves. 

Numerical
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Solution

Given:

  • n1 = 320 Hz
  • n2 = 340 Hz
  • v = 340 m/s

To find:

Difference in wavelength (λ1 − λ2) = ?

Formula:

`lambda_1 = v/n_1 and lambda_2 = v/n_2`

Here, n1 < n2,

∴ λ1 > λ2

∴ `lambda_1 - lambda_2 = 1/n_1 - v/n_2`

∴ `lambda_1 - lambda_2 = v[1/n_1 - v/n_2]`

∴ `lambda_1 - lambda_2 = 340[(340 - 320)/(320 xx 340)]`

∴ `lambda_1 - lambda_2 = 340[20/(320 xx 340)]`

∴ `lambda_1 - lambda_2 = cancel340[20/(320 xx cancel340)]`

∴ `lambda_1 - lambda_2 = 1/16`

∴ `lambda_1 - lambda_2 = 0.0625  m`

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