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Question
Two small circles touching each other externally and of radius 6 cm are inscribed in a circle. Find the shaded area. [Take π = 3.14]

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Solution
Given:
- Two small circles touch each other externally.
- Each small circle has radius 6 cm.
- Both are inscribed in a larger circle, meaning all three centers lie on a straight line and the outer circle encloses both.
Step 1: Find diameter of the larger circle
Since the smaller circles touch each other externally, the distance between their centers is:
6 cm + 6 cm = 12 cm
This segment is part of the diameter of the larger circle.
Add one radius on each side:
Diameter of larger circle = 6 + 12 + 6 = 24 cm
Radius of larger circle = `24/2` = 12 cm
Step 2: Area of the larger circle
A = πr2
= 3.14 × 122
= 3.14 × 144
= 452.16 cm2
Step 3: Area of each small circle
A = πr2
= 3.14 × 62
= 3.14 × 36
= 113.04 cm2
There are two such circles:
2 × 113.04 = 226.08 cm2
Step 4: Shaded area
Shaded area = Area of larger circle – Area of 2 smaller circles
= 452.16 – 226.08
= 226.08 cm2
