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Question
Two numbers are selected from first six even natural numbers at random without replacement. If X denotes the greater of two numbers selected, find the probability distribution of X.
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Solution
The two even natural numbers can be selected from the first six even natural numbers without replacement in 6 × 5 = 30 ways.
X represent the greater of two numbers.
Therefore, X can take the values 4, 6, 8, 10, 12.
For X = 4: Possible observations are (2, 4), (4, 2).
∴ P(X = 4) = `2/30 = 1/15`
For (X = 6): Possible observations are
(2, 6), (6, 2), (4, 6), (6, 4)
P(X = 6) = `4/30 = 2/15`
For X = 8: Possible observations are
(2, 8), (8, 2), (4, 8), (8, 4), (6, 8), (8, 6)
P(X = 8) = `6/30 = 1/5`
For X = 10: Possible observations are
(2, 10), (10, 2), (4, 10), (10, 4), (6, 10), (10, 6), (8, 10), (10, 8)
P(X = 10) = `8/30 = 4/15`
For X = 12: Possible observations are
(2, 12), (12, 2), (4, 12), (12, 4), (6, 12), (12, 6), (8, 12), (12, 8), (10, 12), (12, 10)
P(X = 12) = `10/30 = 1/3`
Therefore, the probability distribution
| X | 4 | 6 | 8 | 10 | 12 |
| P(X) | `1/15` | `2/15` | `1/5` | `4/15` | `1/3` |
