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Question
Two metallic rods, each of length L, area of cross A1 and A2, having resistivities ρ1 and ρ2 are connected in parallel across a d.c. battery. Obtain the expression for the effective resistivity of this combination.
Numerical
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Solution
For resistor R1:
Resistivity = ρ1
Length = L
Area = A1
∴ R1 = `rho_1 xx L/A_1`
For resistor R2:
Resistivity = ρ2
Length = L
Area = A2
∴ R2 = `rho_2 xx L/A_2`
For the equivalent resistor:
Resistivity = ρ
Length = L
Area (A) = A1 + A2
∴ R = `rho xx L/A`
Since the resistors are connected in parallel.
Equivalent resistance (R) = `(R_1 R_2)/(R_1 + R_2)`
Or,
`rho xx L/A = ((rho_1L)/A_1 xx (rho_2L)/A_2)/((rho_1L)/A_1 + (rho_2L)/A_2`
∴ Effective resistivity (ρ) = `(rho_1 rho_2 (A_1 + A_2))/(rho_1 A_2 + rho_2 A_1)`
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