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Question
Two electric lamps of each 40 watt are connected in series. The power consumed by the combination will be
Options
20 Watt
60 Watt
80 Watt
100 Watt
MCQ
Solution
20 Watt
Explanation:
Each bulb's resistance = V2/40 ohm.
Total resistance of two bulbs connected in series
R = `V^2/40 + V^2/40 = V^2/20`
As a result, the effective power of two bulbs is
R = `V^2/R = V^2/(V^2/20)` = 20 watt
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