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Two cyclists start simultaneously from two points A and B, their destinations being B and A, respectively. After crossing each other, they precisely take 2 hours 33 minutes 36 -

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Question

Two cyclists start simultaneously from two points A and B, their destinations being B and A, respectively. After crossing each other, they precisely take 2 hours 33 minutes 36 seconds and I hour 26 minute 24 seconds respectively to reach their destinations. What is the ratio of the speed of the first to that of the second cyclist?

Options

  • 3:4

  • 2:3

  • 3:2

  • 4:3

MCQ

Solution

3:4

Explanation:

Time taken by 1st after crossing T1 = 2 hours 33 minutes 36 seconds = 9216 seconds.

Time taken by 2nd after crossing, T2 = 1 hour 26 minutes 24 seconds = 5184 seconds.

∴ `("Speed of"  1st  (S_1))/("Speed of"  2nd  (S_2)) = sqrt(T_2/T_1) = sqrt(5184/9216) = sqrt(1296/2304)`

= `sqrt(324/576) = 18/24`

⇒ S1 : S2 = 18 : 24 = 3 : 4

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Time, Speed and Distance (Entrance Exam)
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