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Question
Two cyclists start simultaneously from two points A and B, their destinations being B and A, respectively. After crossing each other, they precisely take 2 hours 33 minutes 36 seconds and I hour 26 minute 24 seconds respectively to reach their destinations. What is the ratio of the speed of the first to that of the second cyclist?
Options
3:4
2:3
3:2
4:3
MCQ
Solution
3:4
Explanation:
Time taken by 1st after crossing T1 = 2 hours 33 minutes 36 seconds = 9216 seconds.
Time taken by 2nd after crossing, T2 = 1 hour 26 minutes 24 seconds = 5184 seconds.
∴ `("Speed of" 1st (S_1))/("Speed of" 2nd (S_2)) = sqrt(T_2/T_1) = sqrt(5184/9216) = sqrt(1296/2304)`
= `sqrt(324/576) = 18/24`
⇒ S1 : S2 = 18 : 24 = 3 : 4
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Time, Speed and Distance (Entrance Exam)
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