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Two Cards Are Drawn Without Replacement from a Pack of 52 Cards. Find the Probability that Both Are Kings . - Mathematics

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Question

Two cards are drawn without replacement from a pack of 52 cards. Find the probability that both are kings .

Sum
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Solution

Consider the given events
A = A king in the first draw
B = A king in the second draw

\[\text{ Now } , \]
\[P\left( A \right) = \frac{4}{52} = \frac{1}{13}\]
\[P\left( B/A \right) = \frac{3}{51} = \frac{1}{17}\]
\[ \therefore \text{ Required probability }  = P\left( A \cap B \right)\]
\[ = P\left( A \right) \times P\left( B/A \right)\]
\[ = \frac{1}{13} \times \frac{1}{17}\]
\[ = \frac{1}{221}\]

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Problems based on Probability
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Chapter 31: Probability - Exercise 31.2 [Page 22]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 31 Probability
Exercise 31.2 | Q 6.1 | Page 22
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