Question

Two capillary tubes of same diameter are immersed vertically in two liquids of surface tension 60 dyne cm^-1 and 50 dyne cm^-1 respectively. The rise of liquid in the capillaries is 'h₁' and 'h₂' respectively. If the densities of liquid are 0.8 g/cm³ and 0.6 g/cm³ respectively, then `"h"_1/"h"_2` is ______.

(Neglect the angle of contact)

Options

• `10/3`

• `10/9`

• `9/10`

• `3/10`

Answer 1

Two capillary tubes of same diameter are immersed vertically in two liquids of surface tension 60 dyne cm^-1 and 50 dyne cm^-1 respectively. The rise of liquid in the capillaries is 'h₁' and 'h₂' respectively. If the densities of liquid are 0.8 g/cm³ and 0.6 g/cm³ respectively, then `"h"_1/"h"_2` is `underline(9/10)`.

Explanation:

The rise of liquid is given by

`"h"=(2Tcostheta)/(r rho g)`

`therefore "h"_1/"h"_2=T_1/T_2*rho_2/rho_1=60/50*0.6/0.5=9/10`