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Question
Two capacitors of capacities 2 µF and 4 µF are connected in parallel. A third capacitor of 6µF capacity is connected in series with this combination. A battery of 12 V is connected across this combination. The charge on 2µF capacitor is ______.
Options
12 µC
11 µC
14 µC
16 µC
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Solution
Two capacitors of capacities 2 µF and 4 µF are connected in parallel. A third capacitor of 6µF capacity is connected in series with this combination. A battery of 12 V is connected across this combination. The charge on 2µF capacitor is 12 µC.
Explanation:
The circuit diagram of given situation is as shown below

The equivalent capacitance of 2µF and 4µF capacitors connected in parallel Is
Ceq = 2 + 4 = 6µF
The circuit now becomes

As, both the capacitors are of the same capacitance, so the potential of 12 V is equally divided in them i.e.,
V1 = V2 = 6V
In parallel combination, the potential remains the same.
∴ Charge on 2µF, Q = 2 × V1 = 2 × 6 = 12µC
OR
Let C1 = 2µF, C2 = 4µF and C3 = 6µF
Equivalent of C1 and C2 = C4 = 6µF
Equivalent of C3 and C4 = C5 = 3µF
Charge on C5 = Q = C5 V = 3 × 12 = 36 µC.
C3 and C4 are in series. Hence charge on them is also 36 µC.
The charge of 36 µC is divided between C1 and C2 in proportion to their capacitance.
`Q_1/Q_2 = C_1/C_2`
∴ `Q_1/(Q_1 + Q_2) = C_1/(C_1 + C_2)`
∴ `Q_1/Q = C_1/(C_1 + C_2) = 2/6 = 1/3`
∴ `Q_1 = Q/3 = 36/3 = 12muC`
