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Question
तीन नाणी एकाच वेळी फेकली असता, जर X छापा (head) दर्शवत असेल तर त्या X चे अपेक्षित मूल्य (expected value) व विश्लेषण (variance) काढा.
Sum
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Solution
S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} आणि X = {0, 1, 2, 3}
| X = xi | P = pi | xipi | `bb(x_i^2p_i)` |
| 0 | `1/8` | 0 | 0 |
| 1 | `3/8` | `3/8` | `3/8` |
| 2 | `3/8` | `6/8` | `12/8` |
| 3 | `1/8` | `3/8` | `9/8` |
| `sum_(i = 1)^n x_ip_i = 12/8` | `sum_(i = 1)^n x_i^2p_i = 24/8` |
मग अपेक्षित मूल्य (X) = `sum_(i = 1)^n x_ip_i`
= `12/8`
= 1.5
विश्लेषण (X) = `(sum_(i = 1)^n x_i^2p_i) - (sum_(i = 1)^n x_ip_i)^2`
= `24/8 - (1.5)^2`
= 3 − 2.25
= 0.75
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Is there an error in this question or solution?
