Advertisements
Advertisements
Question
Three resistance each of 4Ω are connected to from a triangle. The resistance b / w two terminal is
Options
12 Ω
6 Ω
`8/3` Ω
2 Ω
MCQ
Solution
`8/3` Ω
Explanation:
The resistance of two triangle arms will be in series (4 + 4 = 8Ω). This resistance will be parallel to the third arm's resistance (= 4Ω).
∴
∴ RAB = `(4 xx 8)/(4 + 8) = 48/12 = (4 xx 8)/(4 xx 3) = 8/3`Ω
shaalaa.com
Potentiometer
Is there an error in this question or solution?