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Question
Three distinct numbers are chosen randomly from the first 50 natural numbers. Find the probability that all the three numbers are divisible by both 2 and 3.
Sum
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Solution
S = {1, 2, 3 ........ 50}
n(S) = 50
E = [no’s divisible by 2 and 3]
E = [6, 12, 18, 24, 30, 36, 42, 48]
n(E) = 8
Probability that all the three numbers are divisible by both 2 and 3.
P(E) = `(""^8"C"_3)/(""^50"C"_3)`
\[\begin{aligned}
& =\frac{\frac{|\underline{8}}{|\underline{3}|\underline{5}}}{\frac{|\underline{50}}{|\underline{3}|\underline{47}}} \\
\end{aligned}\]
= `(8 xx 7 xx 6)/(50 xx 49 xx 48)`
= `1/350`
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