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There were 7,20,000 people in a town. If the population of this town increases at the rate of 5% p.a., find the population at the end of 3 years. - Mathematics

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Question

There were 7,20,000 people in a town. If the population of this town increases at the rate of 5% p.a., find the population at the end of 3 years.

Sum
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Solution

We are asked to find the population of a town after 3 years given a 5% annual growth rate. This is a classic compound growth problem.

Step 1: Formula for population growth

`P_("future") = P_("present") (1 + r/100)^n`

Where:

  • `P_("future")` = population after n years
  • `P_("present")` = 7,20,000
  • r = 5%
  • n = 3 years

Step 2: Substitute the values

`P_("future") = 7,20,000 (1 + 5/100)^3`

`P_("future") = 7,20,000 (1 + 0.05)^3`

`P_("future") = 7,20,000 xx (1.05)^3`

Step 3: Calculate (1.05)3 step by step

  1. 1.05 × 1.05 = 1.1025
  2. 1.1025 × 1.05 = 1.157625

Step 4: Multiply by the initial population

`P_("future") = 7,20,000 xx 1.157625`

`P_("future") ≈ 8,33,490`

The population at the end of 3 years is 8,33,490.

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Chapter 2: Compound Interest - EXERCISE 2C [Page 27]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest
EXERCISE 2C | Q 1. | Page 27
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