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There are three coins. One is two headed coin (having head on both faces), another is a biased coin that comes up heads 75% of the time and third is an unbiased coin.

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Question

There are three coins. One is two headed coin (having head on both faces), another is a biased coin that comes up heads 75% of the time and third is an unbiased coin. One of the three coins is chosen at random and tossed, it shows heads, what is the probability that it was the two headed coin?

Sum
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Solution

Let E1: The coin is head on both sides

E2: the coin is biased

E3: the coin is unbiased

E: The coin tossed shows the head

P(E1) = P(E2) = P(E3) = `1/3`

P(E|E1) = 1

P(E|E2) = 75% = `75/100 = 3/4`

P(E|E3) = `1/2`

Intended process

P(E1|E) = `(P(E_1) xx P(E|E_1))/(P(E_1) xx P(E|E_1) + P(E_2) xx P(E|E_2) + P(E_3) xx P(E|E_3)`

= `(1/3 xx 1)/(1/3 xx 1 + 1/3 xx 3/4 + 1/3 xx 1/2)`

= `1/(1 + 3/4 + 1/2)`

= `4/(4 + 3 + 2)`

= `4/9`

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Chapter 13: Probability - Exercise 13.3 [Page 556]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 13 Probability
Exercise 13.3 | Q 6 | Page 556

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