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The values of dissociation constant of [Cu(NH3)4]2+ and [Co(NH3)6]3+ are 1.0 × 10^−12 and 6.2 × 10^−34 respectively. Which complex would be more stable and why? - Chemistry (Theory)

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Question

The values of dissociation constant of [Cu(NH3)4]2+ and [Co(NH3)6]3+ are 1.0 × 10−12 and 6.2 × 10−34 respectively. Which complex would be more stable and why?

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Solution

  1. The stability of a coordination complex is inversely related to its dissociation constant (Kn).
  2. A lower dissociation constant indicates that the complex is less likely to break apart in solution, meaning it is more stable.
  3. For the complexes [Cu(NH3)4]2+ and [Co(NH3)6]3+, the dissociation constants are 1.0 × 10−12 and 6.2 × 10−34 respectively.
  4. Since [Co(NH3)6]3+ has a much smaller dissociation constant, it is far more stable than [Cu(NH3)4]2+.
  5. This greater stability is due to the higher positive charge on the cobalt ion (Co3+), which attracts ligands more strongly and forms more stable coordinate bonds with ammonia.

Therefore, [Co(NH3)6]3+ is the more stable complex.

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Chapter 9: Coordination Compounds - Review Exercises [Page 541]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 9 Coordination Compounds
Review Exercises | Q 9.81 (a) | Page 541
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