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Question
The value of `tan π/5 + 2 tan (2π)/5 + 4 cot (4π)/5` is ______.
Options
`cot π/5`
`cot (2π)/5`
`cot (4π)/5`
`cot (3π)/5`
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Solution
The value of `tan π/5 + 2 tan (2π)/5 + 4 cot (4π)/5` is `underlinebb(cot π/5)`.
Explanation:
`tan π/5 + 2 tan (2π)/5 + 4 cot (4π)/5`
= `(sin π/5)/(cos π/5) + 2 (sin (2π)/5)/(cos (2π)/5) + 4 (cos (4π)/5)/(sin (4π)/5)`
= `(sin π/5)/(cos π/5) + 2(sin (2π)/5)/(cos (2π)/5) + (4(cos^2 (2π)/5 - sin^2 (2π)/5))/(2 sin (2π)/5 cos (2π)/5)`
= `(sin π/5)/(cos π/5) + 2(sin (2π)/5)/(cos (2π)/5) + (2(cos^2 (2π)/5 - sin^2 (2π)/5))/(sin (2π)/5 cos (2π)/5)`
= `(sin π/5)/(cos π/5) + 2[(sin^2 (2π)/5 + cos^2 (2π)/5 - sin^2 (2π)/5)/(cos (2π)/5 sin (2π)/5)]`
= `(sin π/5)/(cos π/5) + (2 cos (2π)/5)/(sin (2π)/5)`
= `(sin π/5)/(cos π/5) + (2(cos^2 π/5 - sin^2 π/5))/(2sin π/5 cos π/5)`
= `(sin^2 π/5 + cos^2 π/5 - sin^2 π/5)/(sin π/5 cos π/5)`
= `(cos^2 π/5)/(sin π/5 cos π/5)`
= `cot π/5`
