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Question
The value of cos 255° + sin 195° is ______.
Options
`(sqrt(3) - 1)/(2sqrt(2))`
`(sqrt(3) - 1)/sqrt(2)`
`-[(sqrt(3) - 1)/sqrt(2)]`
`(sqrt(3) + 1)/sqrt(2)`
MCQ
Fill in the Blanks
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Solution
The value of cos 255° + sin 195° is `underlinebb(-[(sqrt(3) - 1)/sqrt(2)]`.
Explanation:
Consider cos 255° + sin 195°
= cos(270° – 15°) + sin(180° + 15°)
= –sin15° – sin15°
= –2sin15°
= `-2[(sqrt(3) - 1)/(2sqrt(2))]`
= `-[(sqrt(3) - 1)/sqrt(2)]`
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Trigonometric Functions
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