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The total number of possible isomers for [Pt(NH3)4Cl2]Br2 is ______ (nearest integer). - Chemistry (Theory)

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Question

The total number of possible isomers for [Pt(NH3)4Cl2]Br2 is ______ (nearest integer).

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Solution

The total number of possible isomers for [Pt(NH3)4Cl2]Br2 is 6 (nearest integer).

Explanation:

The complex [Pt(NH3)4Cl2]Br2 can have 6 isomers due to a combination of geometrical isomerism and ionization isomerism:

  1. Geometrical isomerism: The two chloride ions (Cl) can be arranged in two possible ways around the central platinum ion. (cis and trans)
  2. Ionization isomerism: The two Br ions can either be outside or inside the coordination sphere, leading to different isomers.

Thus, combining cis-trans isomerism and ionization isomerism, there are 6 possible isomers.

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Chapter 9: Coordination Compounds - INTEGER TYPE QUESTIONS [Page 548]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 9 Coordination Compounds
INTEGER TYPE QUESTIONS | Q 4. | Page 548
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