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Question
The total energy of a satellite in circular orbit is:
Options
+\[\frac {1}{2}\frac {GMm}{r}\]
-\[\frac {1}{2}\frac {GMm}{r}\]
\[\frac {GMm}{r}\]
0
MCQ
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Solution
-\[\frac {1}{2}\frac {GMm}{r}\]
Explanation:
Total Energy = K.E. + P.E. = ½ GMm/r - GMm/r = -½ GMm/r. The negative total energy indicates the satellite is bound to Earth.
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