Question

The time required to deposit one millimole of monovalent metal by the passage of 9.65 amperes through aqueous solution of metal ion is ____________.

Options

•  100 sec.

• 10 sec.

• 300 sec.

• 30 sec.

Answer 1

The time required to deposit one millimole of monovalent metal by the passage of 9.65 amperes through aqueous solution of metal ion is 10 sec..

Explanation:

Moles of Product deposited = `"I t"/96500 xx "mole ratio"`

0.001 = `(9.65 xx "t")/96500 xx 1` ........(∵ For monovalent metal, mole ratio = 1)

t = 10 sec.