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The thickness of a hollow wooden cylinder is 2 cm. It is 35 cm long and its inner radius is 12 cm. Find the volume of the wood required to make the cylinder assuming it is open at either end. - Mathematics

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Question

The thickness of a hollow wooden cylinder is 2 cm. It is 35 cm long and its inner radius is 12 cm. Find the volume of the wood required to make the cylinder assuming it is open at either end.

Sum
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Solution

Given:

Thickness = 2 cm

Length (height) h = 35 cm

Inner radius r = 12 cm (Required: volume of wood for a hollow cylinder open at both ends.)

Outer radius R = r + thickness = 12 + 2 = 14 cm.

Volume of wood = volume of outer cylinder − volume of inner cylinder = π h (R2 − r2).

Compute R2 − r2

= 142 − 122

= 196 − 144

= 52

Therefore

V = π × 35 × 52 

= 1820 π cm3

Taking π = `22/7`

gives V = `1820 × 22/7`

= 5720 cm3

Using π ≈ 3.1416

V ≈ 5717.5 cm3.

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Chapter 17: Mensuration - Exercise 17A [Page 378]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 17 Mensuration
Exercise 17A | Q 4. | Page 378
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