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The Sum of Reciprocals of Meena’S Ages (In Years ) 3 Years Ago and 5 Years Hence `1/3` Find Her Present Ages. - Mathematics

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Question

The sum of reciprocals of Meena’s ages (in years ) 3 years ago and 5 years hence `1/3` Find her present ages. 

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Solution

Let the present age of Meena be x years
Meena’s age 3 years ago =(x-3)years 

Meena’s age 5 years hence =(x+5) years 

According to the given condition, 

`1/(x-3)+1/(x+5)=1/3` 

⇒`(x+5+x-3)/((x-3)(x+5))=1/3` 

⇒`(2x+2)/(x^2+2x-15)=1/3` 

⇒`x^2+2x-15=6x+6` 

⇒`x^2-4x-21=0` 

⇒`x^2-7x+3x-21=0` 

⇒`x(x-7)+3(x-7)=0` 

⇒`(x-7)(x+3)=0` 

⇒`x-7=0  or  x+3=0` 

⇒`x=7  or  x=-3` 

∴` x=7 `                      (Age cannot be negative)
Hence, the present age of Meena is 7 years. 

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Chapter 10: Quadratic Equations - Exercises 5

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 10 Quadratic Equations
Exercises 5 | Q 39
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