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Question
The sum of the coordination number and oxidation number of metal ‘M’ in the complex [M(en)2Cl2] is ______.
Options
6
8
9
10
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Solution
The sum of coordination number and oxidation number of metal ‘M’ in the complex [M(en)2Cl2] is 8.
Explanation:
en (ethylenediamine) is a bidentate ligand, so each en donates two lone pairs.
2 en ligands contribute 2 × 2 = 4 coordination sites
2 Cl− ligands are monodentate, contributing 2 × 1 = 2 sites
Therefore, the coordination number is 6.
Let the oxidation number of M be x.
en is neutral and each Cl− is −1; total charge = −2
Since the complex is neutral, x − 2 = 0, so x = +2
Sum of coordination number and oxidation number = 6 + 2
= 8
Notes
The answer given in the board solution is incorrect. The value 9 is obtained only if the complex is considered as [M(en)2Cl2]+. However, since the complex given in the question is [M(en)2Cl2] (neutral), the correct answer is 8.
