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The standard emf of a cell, involving one electron charge is found to be 0.591 V at 25°C. The equilibrium constant of the reaction is ______. (F = 96,500 C mol−1) - Chemistry (Theory)

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Question

The standard emf of a cell, involving one electron charge is found to be 0.591 V at 25°C. The equilibrium constant of the reaction is ______. (F = 96,500 C mol−1)

Options

  • 1.0 × 101

  • 1.0 × 105

  • 1.0 × 1010

  • 1.0 × 1030

MCQ
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Solution

The standard emf of a cell, involving one electron charge is found to be 0.591 V at 25°C. The equilibrium constant of the reaction is 1.0 × 1010.

Explanation:

\[\ce{E{^{\circ}_{cell}} = \frac{0.0591}{n} log_10 K_c}\]

∴ \[\ce{0.591 = \frac{0.0591}{1} log_10 K_c}\]

or, \[\ce{log_10 K_c = \frac{0.591}{0.0591}}\]

= 10.0

∴ Kc = 1.0 × 1010

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