Question

The ‘spin-only’ magnetic moment [in units of Bohr magneton, (µ_β)] of Ni²⁺ in aqueous solution would be ______. (Atomic number of Ni = 28)

Options

• 2.84

• 4.90

• 0

• 1.73

Answer 1

The ‘spin-only’ magnetic moment [in units of Bohr magneton, (µ_β)] of Ni²⁺ in aqueous solution would be 2.84.

Explanation:

Ni²⁺ (1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸) has only 2 unpaired electrons. Hence, for Ni²⁺, n = 2 and μ_s = `sqrt(n(n + 2)) = sqrt(2(2 + 2))` = 2.83 BM.