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The solution of dydx+ycotx=cosecx is ______

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Question

The solution of `dy/dx + y cotx = cosecx` is ______ 

Options

  • y sec3x = sec2x + c 

  • y sec2x = x + c 

  • y sinx = x + c

  • y sin2x = x + c

MCQ
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Solution

The solution of `dy/dx + y cotx = cosecx` is y sinx = x + c

Explanation:

`dy/dx + ycotx = cosecx`

Here, P = cot x and Q = cosec x

∴ I.F. = `e^{intcotx dx}`

= `e^{log(sinx)} = sinx`

∴ solution of the given equation is

y (sin x) = `intsin x cosec  x  dx + c`

⇒ y sin x = `int 1  dx + c`

⇒ y sin x = x + c

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