Advertisements
Advertisements
Question
The slope of the line which is perpendicular to a line joining the points (0, 0) and (− 8, 8) is
Options
− 1
1
`1/3`
− 8
Advertisements
Solution
1
Explanation;
Hint:
Slope of a line = `(y_2 - y_1)/(x_2 - x_1)`
= `(8 - 0)/(- 8 - 0)`
= `8/(-8)`
= − 1
Slope of the Perpendicular = 1
APPEARS IN
RELATED QUESTIONS
What is the inclination of a line whose slope is 0
Find the slope of a line joining the points
`(5, sqrt(5))` with the origin
What is the slope of a line perpendicular to the line joining A(5, 1) and P where P is the mid-point of the segment joining (4, 2) and (–6, 4).
If the three points (3, – 1), (a, 3) and (1, – 3) are collinear, find the value of a
The line through the points (– 2, 6) and (4, 8) is perpendicular to the line through the points (8, 12) and (x, 24). Find the value of x.
Show that the given points form a right angled triangle and check whether they satisfy Pythagoras theorem
A(1, – 4), B(2, – 3) and C(4, – 7)
If the points A(2, 2), B(– 2, – 3), C(1, – 3) and D(x, y) form a parallelogram then find the value of x and y.
Let A(3, – 4), B(9, – 4), C(5, – 7) and D(7, – 7). Show that ABCD is a trapezium.
A quadrilateral has vertices at A(– 4, – 2), B(5, – 1), C(6, 5) and D(– 7, 6). Show that the mid-points of its sides form a parallelogram.
If slope of the line PQ is `1/sqrt(3)` then slope of the perpendicular bisector of PQ is
