Question

The roots of the equation px² + qx + r = 0, where p ≠ 0, are given by:

Options

• `x = (-p ± sqrt(q^2 - 4pr))/(2p)`

• `x = (-q ± sqrt(q^2 - 2pr))/(4p)`

• `x = (-q ± sqrt(q^2 - 4pr))/(2p)`

• `x = (-q ± sqrt(q^2 - 4pr))/(2q)`

Answer 1

`bb(x = (-q ± sqrt(q^2 - 4pr))/(2p))`

Explanation:

Given,

⇒ px² + qx + r = 0

Comparing equation px² + qx + r = 0 with ax² + bx + c = 0, we get:

a = p, b = q and c = r

By formula,

`x = (-b ± sqrt(b^2 - 4ac))/(2a)`

Substituting values we get:

`x = (-q ± sqrt(q^2 - 4pr))/(2p)`