Question

The roots of the equation `ax^2+bx+c=0` will be reciprocal each other if 

(a)a=b (b)b=c (c)=a (d)= none of these 

Answer 1

(c) c = a 

Let the roots of the equation `(ax^2+bx+c) be α and 1/α` 

∴ Product of the roots =`αxx1/α=1` 

⇒ `c/a=1` 

⇒` c=a`