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Question
The roots of the equation 2x^2-6x+7=0 are
(a) real, unequal and rational (b) real, unequal and irrational (c) real and equal (d) imaginary
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Solution
(d) imaginary
∵` D=(b^2-4ac)`
=`(-6)^2-4xx2xx7`
=`36-56`
=`-20<0`
Thus, the roots of the equation are imaginary
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