Question

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 ohm. What is the cell constant and molar conductivity of 0.001 M KCl solution, if the conductivity of this solution is 0.146 × 10⁻³ ohm⁻¹ cm⁻¹ at 298 K?

Answer 1

Given: κ = 0.146 × 10⁻³ Ω⁻¹cm⁻¹

Resistance (R) = 1500 Ω

C = 0.001 mol/L

Cell constant (G) = κ × R

= 0.146 × 10⁻³ × 1500

= 0.219 cm⁻¹

Molar conductivity (Λ_m) = `(kappa xx 1000)/C`

= `(0.146 xx 10^(-3) xx 1000)/0.001`

= 146 S cm² mol⁻¹