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The reaction between the red lead and hydrochloric acid is given below: PbA3OA4+8HCl⟶3PbClA2+4HA2O+ClA2 Calculate the volume of the chlorine evolved at S.T.P.

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Question

The reaction between the red lead and hydrochloric acid is given below:

\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]

Calculate the volume of the chlorine evolved at S.T.P.

Numerical
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Solution

1 V Pb3O4 produces 1 V Cl2

685g of Pb3O4has volume = 22.4 litres = volume of Cl2 produced

So, 6.85 Pb3O4 will produce = `(6.85 xx 22.4)/685` = 0.224 litres

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5D [Page 94]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5D | Q 4. (c) | Page 94
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