Question

The reaction between the red lead and hydrochloric acid is given below:

\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]

Calculate the mass of the chlorine.

Answer 1

685g of Pb₃O₄ gives = 71g of Cl₂

Hence, 6.85 g of Pb₃O₄ will give = `(6.85 xx 71)/685` = 0.71 g