Question

The reaction between the red lead and hydrochloric acid is given below:

\[\ce{Pb3O4 + 8HCl -> 3PbCl2 + 4H2O + Cl2}\]

Calculate the mass of lead chloride formed by the action of the 6.85 g of red lead.

Answer 1

Molecular mass of Pb₃O₄ = 3 207.2 + 4 16 = 685 g

685 g of Pb₃O₄ gives = 834 g of PbCl₂

Hence, 6.85 g of Pb₃O₄ will give = `(6.85 xx 834)/685` = 8.34 g