Question

The reaction \[\ce{A + 2B -> C}\] obeys the equation, 

Rate = k[A]^1/2 [B]^3/2

What is the order of the reaction?

Answer 1

The given rate law is

Rate = k[A]^1/2 [B]^3/2

To find the order of the reaction, we add the powers of the concentration terms in the rate law:

Order = `1/2 + 3/2 = 2`

∴ The order of the reaction is 2