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Question
The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction \[\ce{2A + 4B -> 3C + 4D}\], when 5 moles of A react with 6 moles of B, then which is the limiting reagent?
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Solution
The reaction is shown below.
\[\ce{2A + 4B -> 3C + 4D}\]
2 moles of A requires 4 moles of B. So, the number of moles of B required for 5 moles of A is calculated as,
Moles of B = 5 mol of A × `(4 "mol of B")/(2 "mol of A")` = 10 mol of B
So, the required number of moles of B is 10 mol but only 6 moles of B are given in the question.
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