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Question
The ratio of the time required for `3/4`th of the reaction of first order to complete to that required for half of the reaction is ______.
Options
4 : 3
3 : 2
2 : 1
1 : 2
MCQ
Fill in the Blanks
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Solution
The ratio of the time required for `3/4`th of the reaction of first order to complete to that required for half of the reaction is 2 : 1.
Explanation:
We are given a first-order reaction and asked to find the ratio:
`t_(3//4)/t_(1//2) = ?`
For a first-order reaction, the time required to reduce the concentration from [A]0 to [A] is:
`t = 2.303/k log ([A]_0/[A])`
Time for half-reaction:
`t_(1//2) = 2.303/k log 2`
That means [A] = 14 [A]0
`t_(3//4) = 2.303/k log([A]_0/([A]_0//4))`
= `2.303/k log 4`
By taking the ratio:
`t_(3//4)/t_(1//2) = (log 4)/(log 2)`
= `2/1`
= 2 : 1
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