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Question
The rate of the reaction,
\[\ce{CCl3CHO + NO -> CHCl3 + NO + CO}\]
is given by the equation, rate = k [CCl3CHO)[NO]. If concentration is expressed in mol/litre, the units of k are ______.
Options
mol−2 L2 s−1
mol L−1 s−1
mol−1 L s−1
s−1
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Solution
The rate of the reaction,
\[\ce{CCl3CHO + NO -> CHCl3 + NO + CO}\]
is given by the equation, rate = k [CCl3CHO)[NO]. If concentration is expressed in mol/litre, the units of k are mol−1 L s−1.
Explanation:
The given reaction is
\[\ce{CCl3CHO + NO -> CHCl3 + NO + CO}\]
Rate law: rate = k [CCl3CHO)[NO]
This implies the reaction is first order in each reactant and second order overall.
Rate has units mol L−1 s−1
Each concentration is mol L−1
From rate = k [CCl3CHO)[NO]
⇒ k = `"Rate"/(["CCl"_3"CHO"]["NO"])`
⇒ Units of k = `(mol L^-1 s^1)/((mol L^-1)^2)`
= mol−1 L s−1
