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The rate of reaction, A+BProducts, is given by the equation, r = k [A] [B]. If B is taken in large excess, the order of reaction would be ______. - Chemistry (Theory)

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Question

The rate of reaction, \[\ce{A + B -> Products}\], is given by the equation, r = k [A] [B]. If B is taken in large excess, the order of reaction would be ______.

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  • 1

  • 0

  • unpredictable

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Solution

The rate of reaction, \[\ce{A + B -> Products}\], is given by the equation, r = k [A] [B]. If B is taken in large excess, the order of reaction would be 1.

Explanation:

The given rate law is r = k [A] [B]

This shows the reaction is second order overall (1 in A + 1 in B).

If [B] is very large and constant, then its concentration does not change appreciably during the course of the reaction.

So, we can combine k[B] as a new constant, k'.

r = k [A] [B] ≈ k'[A]

Now, the reaction behaves like a pseudo-first order reaction with respect to A.
So, the effective order = 1.

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Chapter 4: Chemical Kinetics - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [Page 267]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 4 Chemical Kinetics
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 4. | Page 267
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