Question

The range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be 

Options

• 25 m

• 37 m

• 50 m

• 100 m

Answer 1

100 m
For the same u range, \[R \propto \sin\left( 2\theta \right)\] .

So, \[\frac{R_1}{R_2} = \frac{\sin\left( 2 \theta_1 \right)}{\sin\left( 2 \theta_2 \right)}\]

\[\Rightarrow R_2 = 50 \times \frac{\sin\left( 90 \right)}{\sin\left( 30 \right)} = 100 \text{ m } \]