Question

The radius of a ball is (6.2 ± 0.4) cm. The percentage error in the volume of the ball is

______.

Options

• 11%

• 4%

• 19%

• 9%

Answer 1

The radius of a ball is (6.2 ± 0.4) cm. The percentage error in the volume of the ball is 19%.

Explanation:
Volume \[V=\frac{4}{3}\pi r^3\]

Percentage error in V = 3 × (Δr / r) × 100
= 3 × (0.4 / 6.2) × 100 ≈ 3 × 6.45% ≈ 19%