Question

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is ______.

Options

• 4950 cm²

• 4951 cm²

• 4952 cm²

• 4953 cm²

Answer 1

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is 4950 cm².

Explanation:

Given, the radius of the top of the bucket, R = 28 cm

And the radius of the bottom of the bucket, r = 7 cm

Slant height of the bucket, l = 45 cm

Since, bucket is in the form of frustum of a cone.

∴ Curved surface area of the bucket = πl (R + r)

= π × 45(28 + 7)    ...[∵ Curved surface area of frustum of a cone = π(R + r)l]

= π × 45 × 35

= `22/7 xx 45 xx 35`

= 4950 cm²