English
Karnataka Board PUCPUC Science 2nd PUC Class 12

The Q value of a nuclear reaction A + b → C + d is defined by Q = [mA+ mb − mC − md]c2 where the masses refer to the respective nuclei. - Physics

Advertisements
Advertisements

Question

The Q value of a nuclear reaction A + b → C + d is defined by

Q = [mA+ mb − mC − md]c2 where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic.

\[\ce{^12_6C + ^12_6C ->^20_10Ne + ^4_2He}\]

Atomic masses are given to be

`"m"(""_1^2"H")` = 2.014102 u

`"m"(""_1^3"H")` = 3.016049 u

`"m"(""_6^12C)` = 12.000000 u

`"m"(""_10^20"Ne")` = 19.992439 u

Numerical
Advertisements

Solution

The given nuclear reaction is:

\[\ce{^12_6C + ^12_6C ->^20_10Ne + ^4_2He}\]

t is given that:

Atomic mass of `"m"(""_6^12"C") = 12.0 u`

Atomic mass of `"m"(""_10^20"Ne")` = 19.992439 u

Atomic mass of `"m"(""_2^4"He")` = 4.002603 u

The Q-value of this reaction is given as:

`"Q" = [2"m"(""_6^12"C") - "m"(""_10^20"Ne") - "m"(""_2^4"He")]"c"^2`

`= [2 xx 12.0 - 19.992439 - 4.002603]"c"^2`

`= (0.004958 c^2)"u"`

`= 0.004958 xx 931.5 = 4.618377` MeV

The positive Q-value of the reaction shows that the reaction is exothermic.

shaalaa.com
  Is there an error in this question or solution?

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Derive the mathematical expression for law of radioactive decay for a sample of a radioactive nucleus


The half-life of `""_38^90 "Sr"` is 28 years. What is the disintegration rate of 15 mg of this isotope?


The Q value of a nuclear reaction \[\ce{A + b → C + d}\] is defined by

Q = [ mA+ mb− mC− md]cwhere the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic.

\[\ce{^1_1H + ^3_1H -> ^2_1H + ^2_1H}\]

Atomic masses are given to be

`"m"(""_1^2"H")` = 2.014102 u

`"m"(""_1^3"H")` = 3.016049 u

`"m"(""_6^12"C")` = 12.000000 u

`"m"(""_10^20"Ne")` = 19.992439 u


A source contains two phosphorous radio nuclides `""_15^32"P"` (T1/2 = 14.3d) and `""_15^33"P"` (T1/2 = 25.3d). Initially, 10% of the decays come from `""_15^33"P"`. How long one must wait until 90% do so?


Under certain circumstances, a nucleus can decay by emitting a particle more massive than an α-particle. Consider the following decay processes:

\[\ce{^223_88Ra -> ^209_82Pb + ^14_6C}\]

\[\ce{^223_88 Ra -> ^219_86 Rn + ^4_2He}\]

Calculate the Q-values for these decays and determine that both are energetically allowed.


In a given sample, two radioisotopes, A and B, are initially present in the ration of 1 : 4. The half lives of A and B are respectively 100 years and 50 years. Find the time after which the amounts of A and B become equal.


In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following particles is emitted in the decay?


The decay constant of a radioactive sample is λ. The half-life and the average-life of the sample are respectively


28Th emits an alpha particle to reduce to 224Ra. Calculate the kinetic energy of the alpha particle emitted in the following decay:

`""^228"Th" → ""^224"Ra"^(∗) + alpha`

`""^224"Ra"^(∗) → ""^224"Ra" + γ (217 "keV")`.

Atomic mass of 228Th is 228.028726 u, that of 224Ra is 224.020196 u and that of  `""_2^4H` is 4.00260 u.

(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)


Calculate the maximum kinetic energy of the beta particle emitted in the following decay scheme:
12N → 12C* + e+ + v
12C* → 12C + γ (4.43MeV).
The atomic mass of 12N is 12.018613 u.

(Use Mass of proton mp = 1.007276 u, Mass of `""_1^1"H"` atom = 1.007825 u, Mass of neutron mn = 1.008665 u, Mass of electron = 0.0005486 u ≈ 511 keV/c2,1 u = 931 MeV/c2.)


When charcoal is prepared from a living tree, it shows a disintegration rate of 15.3 disintegrations of 14C per gram per minute. A sample from an ancient piece of charcoal shows 14C activity to be 12.3 disintegrations per gram per minute. How old is this sample? Half-life of 14C is 5730 y.


A radioactive isotope is being produced at a constant rate dN/dt = R in an experiment. The isotope has a half-life t1/2. Show that after a time t >> t1/2 the number of active nuclei will become constant. Find the value of this constant.


Identify the nature of the radioactive radiations emitted in each step of the decay process given below.

`""_Z^A X -> _Z^A  _-1^-4 Y ->_Z^A  _-1^-4 W`


A radioactive substance disintegrates into two types of daughter nuclei, one type with disintegration constant λ1 and the other type with disintegration constant λ2 . Determine the half-life of the radioactive substance.


What is the amount of \[\ce{_27^60Co}\] necessary to provide a radioactive source of strength 10.0 mCi, its half-life being 5.3 years?


A radioactive element disintegrates for an interval of time equal to its mean lifetime. The fraction that has disintegrated is ______


Which one of the following nuclei has shorter meant life?

 


Samples of two radioactive nuclides A and B are taken. λA and λB are the disintegration constants of A and B respectively. In which of the following cases, the two samples can simultaneously have the same decay rate at any time?

  1. Initial rate of decay of A is twice the initial rate of decay of B and λA = λB.
  2. Initial rate of decay of A is twice the initial rate of decay of B and λA > λB.
  3. Initial rate of decay of B is twice the initial rate of decay of A and λA > λB.
  4. Initial rate of decay of B is the same as the rate of decay of A at t = 2h and λB < λA.

A piece of wood from the ruins of an ancient building was found to have a 14C activity of 12 disintegrations per minute per gram of its carbon content. The 14C activity of the living wood is 16 disintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given half-life of 14C is 5760 years.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×