Question

The projection vector of vector `veca` on vector `vecb` is ______.

Options

• `((veca  .  vecb)/|vecb|^2)vecb`

• `(veca  .  vecb)/|vecb|`

• `(veca  .  vecb)/|veca|`

• `((veca  .  vecb)/|veca|^2)vecb`

Answer 1

The projection vector of vector of vector `veca` on vector `vecb` is `bbunderline(((veca  .  vecb)/|vecb|^2)vecb)`.

Explanation:

Projection vector of `veca  "on"  vecb = ((veca  .  vecb)/|vecb|)hatb`

= `((veca  .  vecb)/|vecb|)(vecb)/|vecb|       ...[∵ hatb = vecb/|vecb|]`

= `((veca  .  vecb)/|vecb|^2)vecb`